An Open Access Journal
Process | Parameter | Equation |
---|---|---|
Arrival distribution of the passenger at the airport [min] | μ = 89; σ = 26 | \( p(x)=\frac{1}{\sigma \sqrt{2\pi }}{e^{-\frac{1}{2}\left(\frac{x-\mu }{\sigma}\right)}}^2 \) |
Duration Check-in [min] | μ=58; σ= 25 | |
Deposition of personal belongings at the security control [min] | a = 0; b = 81 mode=21 | \( p(x)=\left\{\begin{array}{c}\frac{2\left(x-a\right)}{\left(b-a\right)\left(c-a\right)}\kern2em for\ x\in \left[a,c\right]\\ {}\frac{2\left(b-c\right)}{\left(b-a\right)\left(b-c\right)}\kern1.75em for\ x\in \left[c,b\right]\\ {}0\kern6.25em else\end{array}\right. \) |
Security check of person and luggage [min] | a = 2; b = 169 mode = 43 | |
Receiving of personnel belongings at the security control [min] | a = 0; b = 260 mode= 22 | |
Duration Passport control [s] | a = 50; b = 60 | \( p(x)=\left\{\begin{array}{c}\frac{1}{\left(b-a\right)}\kern2.5em for\ a\le x\le b\\ {}0\kern7.5em else\end{array}\right. \) |
Calculation of delay times in the airport terminal [m/s] | v = 1.34 dv = 0.26 | \( t=\frac{s}{v} \) \( dt=\sqrt{{\left(\frac{1}{v}\right)}^2\ast {ds}^2+{\left(\frac{s}{v^2}\right)}^2\ast {dv}^2} \) |