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Table 7 Input data of various test problems

From: Variants of transshipment problem

Test problem no.

Problem no./type

Order of

Original availability and demand of the transshipment problem

Buffer stock (T)

Availability and demand of the transformed transportation problem with dummy point source/destination

Original transshipment problem

Transformed transportation problem

 7.1

Impaired Flow (P4) P ′ = 40

2 × 2

5 × 5

a 1 = 4, a 2 = 5, b 3 = 3, b 4 = 6

9

a 1 = 13, a 2 = 14, a 3 = 9, a 4 = 9, b 1 = 9, b 2 = 9, b 3 = 12, b 4 = 15, a 5 = 5, b 6 = 5

 7.2

Enhanced Flow (P6) P ′ = 48

 7.3

Impaired Flow (P4) P ′ = 115

2 × 2

5 × 5

a 1 = 8, a 2 = 12, b 3 = 15, b 4 = 10

25

a 1 = 33, a 2 = 37, a 3 = 25, a 4 = 25, b 1 = 25, b 2 = 25, b 3 = 40, b 4 = 35, a 5 = 10, b 6 = 5

 7.4

Enhanced Flow (P6) P ′ = 130

 7.5

Impaired Flow (P4) P ′ = 540

5 × 5

11 × 11

a 1 = 10, a 2 = 12, a 3 = 5, a 4 = 15, a 5 = 8, b 6 = 8, b 7 = 11, b 8 = 9, b 9 = 10, b 10 = 4

50

a 1 = 60, a 2 = 62, a 3 = 55, a 4 = 65, a 5 = 58, a 6 = 50, a 7 = 50, a 8 = 50, a 9 = 50, a 10 = 50, b 1 = 50, b 2 = 50, b 3 = 50, b 4 = 50, b 5 = 50, b 6 = 58, b 7 = 61, b 8 = 59, b 9 = 60, b 10 = 54, a 11 = 2, b 11 = 10

 7.6

Enhanced Flow (P6) P ′ = 555

All values are same as impaired flow except dummy points a 11 = 5, b 11 = 13

 7.7

Case-I

(P8)

2 × 2

4 × 5

a 1 = 7, a 2 = 5, b 3 = 3, b 4 = 6

12

a 1 = 19, a 2 = 17, a 3 = 12, a 4 = 12, b 1 = 12, b 2 = 12, b 3 = 15, b 4 = 18, b 5 = 3

 7.8

(P10)

2 × 2

5 × 4

a 1 = 4, a 2 = 5, b 3 = 8, b 4 = 6

14

a 1 = 18, a 2 = 19, a 3 = 14, a 4 = 14, b 1 = 14, b 2 = 14, b 3 = 22, b 4 = 20, a 5 = 5

 7.9

Case-II

(P12)

2 × 2

5 × 4

a 1 = 4, a 2 = 5, b 3 = 7, b 4 = 10

17

a 1 = 21, a 2 = 22, a 3 = 17, a 4 = 17, b 1 = 17, b 2 = 17, b 3 = 24, b 4 = 27, a 5 = 8

 7.10

(P13)

2 × 2

4 × 5

a 1 = 8, a 2 = 7, b 3 = 3, b 4 = 6

15

a 1 = 23, a 2 = 22, a 3 = 15, a 4 = 15, b 1 = 15, b 2 = 15, b 3 = 18, b 4 = 21, b 5 = 6

 7.11

Case-III

(P14)

2 × 2

4 × 5

a 1 = 8, a 2 = 12, b 3 = 4, b 4 = 7

20

a 1 = 28, a 2 = 32, a 3 = 20, a 4 = 20, b 1 = 20, b 2 = 20, b 3 = 24, b 4 = 27, b 5 = 9

 7.12

(P15)

2 × 2

5 × 4

a 1 = 4, a 2 = 10, b 3 = 10 b 4 = 15

25

a 1 = 29, a 2 = 35, a 3 = 25, a 4 = 25, b 1 = 25, b 2 = 25, b 3 = 35, b 4 = 40, a 5 = 11